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    • THR32
      THR32 last edited by

      Problem for the same command line. two different results:
      To calculate the volume of a can, we can use the mathematical formula for the volume of a cylinder, which is V = πr²h, where V is the volume, r is the radius of the base of the cylinder, h is the height of the cylinder and π is a constant approximately equal to 3.14159.

      In this case, the diameter of the can is 32 cm, which means that the radius (r) is half the diameter, or 16 cm (32 cm / 2 = 16 cm). The height of the can is 47 cm.

      Let's apply these values to the formula:

      V = πr²h

      V = 3.14159 * (16 cm)² * 47 cm

      Now let's calculate the volume:

      V = 3.14159 * 256 cm² * 47 cm

      V ≈ 3.14159 * 256 cm² * 47 cm

      V ≈ 38,484.352 cm³

      The volume of the container is approximately 38,484 cm³.

      The second
      To calculate the volume of a can, we can use the mathematical formula for the volume of a cylinder, which is V = πr²h, where V is the volume, r is the radius of the base of the cylinder, h is the height of the cylinder and π is a constant approximately equal to 3.14159.

      In this case, the diameter of the can is 32 cm, which means that the radius (r) is half the diameter, or 16 cm (32 cm / 2 = 16 cm). The height of the container is 47 cm.

      Let's apply these values to the formula:

      V = πr²h

      V = 3.14159 * (16 cm)² * 47 cm

      Now let's calculate the volume:

      V = 3.14159 * 256 cm² * 47 cm

      V ≈ 3.14159 * 256 cm² * 47 cm

      V ≈ 121.212 cm² * 47 cm

      V ≈ 5,699.994 cm³

      The volume of the can is approximately 5,700 cm³.

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      • Locked by  leocg leocg 
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