<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[[Opera Mail] How to export Contacts with intact folder structure]]></title><description><![CDATA[<p dir="auto">Pretty much what the title say.<br />
What I'm doing now:</p>
<p dir="auto">. I export my Conctacts in the .adr file<br />
. I convert to a .csv file following this procedure <a href="http://znos.hu/ohparser/" target="_blank" rel="noopener noreferrer nofollow ugc">http://znos.hu/ohparser/</a></p>
<p dir="auto">but the problem is that the file I obtain does not contain any information about the original Opera Mail Contacts folder structure. I have a collection that I built in years of eperience and cleaning and I don't want to waste it.<br />
If it was just for the top folders I could just export the folders one at the time but I have also alot of subfolders there...<br />
Anyone has a clue of what I'm asking for?</p>
]]></description><link>https://forums.opera.com/topic/3360/opera-mail-how-to-export-contacts-with-intact-folder-structure</link><generator>RSS for Node</generator><lastBuildDate>Thu, 16 Jul 2026 17:41:25 GMT</lastBuildDate><atom:link href="https://forums.opera.com/topic/3360.rss" rel="self" type="application/rss+xml"/><pubDate>Thu, 12 Jun 2014 09:55:23 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to [Opera Mail] How to export Contacts with intact folder structure on Sat, 05 Jul 2014 09:59:46 GMT]]></title><description><![CDATA[<p dir="auto">Thank you burnout426, opera forum isn't warning me about replies. I've seen your post now. I'll have to look at it better this week and do some tests.<br />
Anyway thank you again (as usual).</p>
]]></description><link>https://forums.opera.com/post/44421</link><guid isPermaLink="true">https://forums.opera.com/post/44421</guid><dc:creator><![CDATA[arkanoiz]]></dc:creator><pubDate>Sat, 05 Jul 2014 09:59:46 GMT</pubDate></item><item><title><![CDATA[Reply to [Opera Mail] How to export Contacts with intact folder structure on Sat, 14 Jun 2014 02:35:55 GMT]]></title><description><![CDATA[<p dir="auto">If I export Gmail's contacts to Outlook CSV, I see that there's a semi-colon-separated list of groups the contact is in, in the last column (called the "categories" column according to the header in the csv file). For example:</p>
<pre><code>bob,,,,,,,,,,,,,,bob@example.com,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,Normal,,My Contacts;tester,
</code></pre>
<p dir="auto">So, an adr converter would have to convert Opera's contact folders (merging the sub folders into the top-level folders) into a semi-colon-separated list of groups that the Gmail contact importer can recognize.</p>
<p dir="auto">If I export in google csv format, the list of groups a contact is in is listed in the Group Membership column.</p>
<pre><code>Bob,Bob,,,,,,,,,,,,,,,,,,,,,,,,,* My Contacts ::: tester,* ,bob@gmail.com,,,,,,,,
</code></pre>
<p dir="auto">So, an adr to csv converter should be able to use that format so you can import folders into groups.</p>
<p dir="auto">But, I don't know of a converter that does that.</p>
<p dir="auto">If you don't have too many contacts, you might want to just take the time to add the group entries into the file manually via some find and replace tricks (maybe regex in notepad++) (instead of taking time searching for a converter that does it for you). But, if you have a zillion contacts, that'd be too much trouble. Then again, it might just be faster to create the groups in Gmail's contacts and apply them to each contact.</p>
]]></description><link>https://forums.opera.com/post/42177</link><guid isPermaLink="true">https://forums.opera.com/post/42177</guid><dc:creator><![CDATA[burnout426]]></dc:creator><pubDate>Sat, 14 Jun 2014 02:35:55 GMT</pubDate></item><item><title><![CDATA[Reply to [Opera Mail] How to export Contacts with intact folder structure on Thu, 12 Jun 2014 14:13:26 GMT]]></title><description><![CDATA[<p dir="auto">Ehi thank you sgunhouse for yuor reply.<br />
I'm still looking at a solution since Gmail doesn't support subgroups (only groups). Or I could use Gmail anyway, and try using labels instead of subgroups.<br />
But opening the .csv file in a spreadsheet I don't see any "folders" column; the first one is "Name", the second is "E-mail" ecc. All the entries of the .adr file like:</p>
<p dir="auto">FOLDER<br />
ID=25<br />
NAME=Eventi<br />
CREATED=1382448898<br />
UNIQUEID=07D971355B4C434795D7C4CDE6B22598</p>
<p dir="auto">seem to be ignored. So how could this data be read anyway?</p>
]]></description><link>https://forums.opera.com/post/42076</link><guid isPermaLink="true">https://forums.opera.com/post/42076</guid><dc:creator><![CDATA[arkanoiz]]></dc:creator><pubDate>Thu, 12 Jun 2014 14:13:26 GMT</pubDate></item><item><title><![CDATA[Reply to [Opera Mail] How to export Contacts with intact folder structure on Thu, 12 Jun 2014 10:39:00 GMT]]></title><description><![CDATA[<p dir="auto">Does the program or site you are exporting the contacts to support folders? Ask them if there is a way to import contacts with folder structure intact.</p>
]]></description><link>https://forums.opera.com/post/42058</link><guid isPermaLink="true">https://forums.opera.com/post/42058</guid><dc:creator><![CDATA[sgunhouse]]></dc:creator><pubDate>Thu, 12 Jun 2014 10:39:00 GMT</pubDate></item></channel></rss>